### Loading and haulage

Loading and hauling of blasted ore is done using Cavo 310 or similar machine type with following specifications:

Weight | 3150kg |

Body capacity | 1m^{3} |

Bucket capacity | 0.13m^{3} |

Net. loading capacity | 0.7m^{3}/min |

Tгavel speed | 1-1.4m/s |

Аiг consumption, aveгage | 133l/s |

Аiг pгessure гequiгement | 4-7bar |

Min. tunnel dimensions | 2620x2420mm (w x h) |

Volume of ore produced by one blast:

$$V=1.4\cdot w\cdot h\cdot {{l}_{bh}}\cdot 0.95=3\cdot 2.5\cdot 1.6\cdot 1.4\cdot 0.95\approx 16{{m}^{3}}$$

Where:

W – width of stope (3m)

h – height of stope (2.5m)

l_{bh} – length of blasthole (1.6m)

Total number of cycles necessary to transfer this amount of ore to the ore pass is:

$${{N}_{c}}=\frac{16{{m}^{3}}}{{{V}_{cb}}\cdot 0.9}=\frac{16}{1\cdot 0.9}\approx 18 cycles$$

Where:

V_{cb} – Volume of Cavo 310 body (1m^{3})

Each cycle consists of loading, driving to the ore pass, dumping and returning drive. Duration of one cycle is equal to the sum of durations of each separate operation.

Loading of one Cavo 310 takes following time:

$${{T}_{l}}=\frac{{{V}_{cb}}\cdot 0.9}{{{V}_{b}}}\cdot {{t}_{l}}=\frac{1{{m}^{3}}\cdot 0.9}{0.13{{m}^{3}}}\cdot 15s\approx 100s$$

Where:

V_{cb} – Cavo 310 body volume

V_{b} – bucket volume

t_{l} – time for loading of one bucket

**Figure 23** Longest transportation distance at the level L+1600m

Total driving time can last up to:

$${{T}_{D}}=\frac{{{L}_{T}}}{\upsilon }=\frac{2\cdot 140m}{1m/s}=280s$$

Where:

L_{T} – maximum total driving distance (2 x 140m see Figure 23)

$\upsilon$ – driving velocity (1m/s)

For dumping, maneuvering and all unexpected pauses 40s is left within each cycle and therefore total duration of one loading and hauling cycle is:

$${{T}_{LHC}}=280s+100s+40s=420s=7\min $$

Total duration of loading and hauling of one blasted face takes up to:

$${{T}_{LH}}={{T}_{LHC}}\cdot {{N}_{c}}=7\min \cdot 18=126\to 130\min $$

**Table 2** Gantt chart for loading and haulage